WebJan 11, 2024 · A concave mirror is designed so that a person 20.0 cm in front of the mirror sees an upright image magnified by a factor of two. What is the radius of curvature of this mirror? If you have a concave mirror whose focal length is 100.0 cm, and you want an image that is upright and 10.0 times as tall as the object, where should you place the … WebObject distance, u = – 20 c m. Object height, h = 5 c m. The radius of curvature, R = 30 c m. The radius of curvature = 2 × F o c a l l e n g t h = 30 c m. Step (2) Finding the focal length of the convex mirror: We know that, R = 2 f. f = 15 c m. Step (3) Finding the distance of the image: According to the mirror formula, 1 v − 1 u = 1 f ... clear cache discord WebA concave mirror can produce a magnified virtual image when the object is placed between pole and focus: From this ray diagram, we can say: Image is erect, virtual, and … clear cached credentials windows 7 command-line WebProblem (2): A candle 6 cm tall is placed at a distance of 8 cm in front of a concave mirror whose radius of curvature is 20 cm. Determine the position, size, orientation, and nature (real or virtual) of the image. Solution: … WebThe distance between the car and mirror is called the object distance, and it’s always positive. If you look at the image of the toy car in the mirror, it will appear to be the same distance behind the mirror as the real car is in front of the mirror, at the same height. It will also appear to be the same size as the real car. east midlands housing coalville WebMar 24, 2024 · Example 2: The distance of an object of height 6 cm from a concave lens is 20 cm. If its focal length is 10 cm, calculate the size and position of the image formed. Solution: As the lens here is concave, the focal length (f) = -10 cm. Object distance (o) = + 20 cm . Now by putting the values of (f) and (o) in 1/v+ 1/o = 1/f, we will get, 1/v ...

WebAnswer (1 of 2): Sol^n :- U = -6 cm f = -10 cm Now we know the formula that is :- 1/f = 1/v - 1/u 1/-10 = 1/v - 1/-6 -(1/10) - (1/6 ) = 1/v After solving , V = -3.75 cm Now, M = he/ho= -v/u … WebAn object is placed 30 cm in front of a converging lens with focal length 10 cm. Find the object distance and magnification. Example An object is placed 30 cm in front of a converging lens with focal length 10 cm. Find the object distance and magnification. Ray diagram. 11 1 pq f + = 111 qf p = − fp q pf = − (10)(30) 15cm 30 10 == − q15 ... east midlands housing coalville number WebThe tooth is 1.00 cm in front of the mirror, and the image is formed 10.0 cm behind the mirror. Determine (a) the mirrors radius of curvature and (b) the magnification of the … WebFocal length of mirror. A = 20cm. B = 15cm. C = 10cm. Object distances for these mirrors are 30cm, 10cm and 20cms respectively. 1) Mirror C will produce an image of the same size as an object because the object is placed on C. 2) Mirror B can be used as shaving mirror because when the object is kept between P and F we get virtual, erect and ... clear cached credentials windows 10 WebIf a concave mirror has a focal length of 10cm, find the two positions where an object can be placed to give, in each case, an image twice the height of the object. ... A magnified, … WebA 10cm long object is placed in front of a concave mirror of focal length 20cm, at a distance of 30cm from it. What is the position of the image? If a concave mirror has a focal length of -5.0 cm, what is the location of the object if the image is 10.0 cm from the mirror? clear cache discord ios WebGiven Focal length f10cm Object distance u is placed at a distance that is twice the focal length u2fTherefore u10220cm After applying the mirrors formula 1f1v1u ...

WebThe tooth is 1.00 cm in front of the mirror, and the image is formed 10.0 cm behind the mirror. Determine (a) the mirrors radius of curvature and (b) the magnification of the image. The image formed by a convex spherical mirror with a focal length of magnitude 12.0 cm is located one-fourth of the object-mirror distance from the mirror. a. east midlands housing apprenticeship WebMar 13, 2024 · If a virtual image of 10 cm tall was formed behind the mirror, find the focal length of the mirror and the position of the image. Name the type of mirror used. 5. NA 42 Find the position of an object which when placed in front of a concave mirror of focal length 10 cm virtual image which is twice the size of the object. 6. clear cache discord mac