The zeroes of the quadratic polynomial x^2 + 99x + 127 are?

The zeroes of the quadratic polynomial x^2 + 99x + 127 are?

WebGiven, the quadratic polynomial is x² + kx + k. We have to find the zeros of the polynomial. We know that, if 𝛼 and ꞵ are the zeroes of a polynomial ax^2 + bx + c, then. Sum of the roots is 𝛼 + ꞵ = -b/a. Product of the roots is 𝛼ꞵ = c/a. Where, a = coefficient of x² term. b = coefficient of x term. c = coefficient of constant term WebAug 23, 2024 · ⇒ x = - 1.3, - 97.7. Both the zeroes are negative. OR. We know, in quadratic polynomial if the coefficients of the terms are of the same sign, then the … dr. winter andreas texing WebMar 13, 2024 · The zeroes of the quadratic polynomial ${x^2} + 99x + 127$ are (a) both positive(b) both negative(c) one positive and one negative(d) both equal. Ans: Hint – In … WebMar 22, 2024 · Transcript. Question 9 The zeroes of the quadratic polynomial x2 + 99x + 127 are: both positive (b) both negative (c) one positive and one negative (d) both equal Let p (x) = x2 + 99x + 127 … dr wintenberger athis mons WebSep 15, 2024 · The product of zeroes is positive. So either 'both zeroes are positive' or 'both zeroes are negative'. The zeroes are not equal as discriminant of x2+ 99x + 127 = Ö [992 – 4 (127)] is not equal to zero. The sum of zeroes is negative and the product of the zeroes is positive. So we can conclude that 'both the zeroes of the polynomial are ... WebThe zeroes of the quadratic polynomial x^2 + 99x + 127 areA. Both positive B.… The zeroes of the quadratic polynomial x^2 + kx + k where k≠0,A. Cannot both be… If the zeroes of the quadratic polynomial ax^2 + bx + c, where c≠0, are equal,… If one of the zeroes of a quadratic polynomial of the form x^2 + ax + b is the… dr winterhoff celle hno WebApr 6, 2024 · Let polynomial p(x) = x 2 + 99x + 127 Product of the zeroes of p(x) = 127 (product of zeroes = c/a for ax 2 + bx + c) Since the product of its zeroes is positive, we can say that it is only possible when 'both zeroes are positive' or 'both zeroes are negative'. The zeroes are not equal as discriminant for p(x) = is definitely not zero.

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