Answered: An electric lamp whose resistance, when… bartleby?

Answered: An electric lamp whose resistance, when… bartleby?

WebMay 20, 2014 · An electric lamp, whose resistance is 20Ω and a conductor of 4Ω resistance are connected to a 6V battery ... The potential difference across the electric lamp = 0.25 ×20 = 5 volt The potential difference across the conductor = 0.25 × 4 = 1volt. Recommend (2) Comment (0) ASK A QUESTION . WebA 6 V battery is connected across a lamp whose resistance is 20 Ω . Calculate the value of the extra resistance in Ω which must be used in the circuit to get 0.25 A current in the circuit. A. 4 ΩB. 6 ΩC. 2 ΩD. 8 Ω coatue growth fund v private investors l.l.c Web374 views, 15 likes, 11 loves, 14 comments, 3 shares, Facebook Watch Videos from الصفحة الرسمية لمتوسطة يرفع محمد: أجواء اللقاء الثقافي بين متوسطتي يرفع... WebJun 17, 2024 · An electric lamp, whose resistance is 20 and a conductor of 40 resistance a connected to a 6v battery, then the amount of current passing through the circuit is A. 6 … coatue hedge fund aum WebSimple to use Ohm's Law Calculator. Calculate Power, Current, Voltage or Resistance. Just enter 2 known values and the calculator will solve for the others. WebAnswer: (a) Resistance of electric lamp, R 1 = 20 W Resistance of series conductor, R ² = 4 W Total resistance in the circuit,Rs = R 1 + R ² = 20 Ω + 4 Ω = 24 Ω. (b) Total potential difference, V = 6 V By Ohm’s law, the current through the circuit is (c) Potential difference across the electric lamp, V ¹ = IR ¹ = 0.25 A × 20 Ω = 5 V. da black sheep WebApr 16, 2024 · Q.7 An electric lamp, whose resistance is 20 Ω, and a conductor of 4 Ω resistance are connected to a 6 V battery (Fig. 12.9). Calculate (a) the total resistance …

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